98-50x^2=0

Solution for 98-50x^2=0 equation:

98-50x^2=0

a = -50; b = 0; c = +98;
Δ = b2-4ac
Δ = 02-4·(-50)·98
Δ = 19600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{19600}=140$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-140}{2*-50}=\frac{-140}{-100}
=1+2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+140}{2*-50}=\frac{140}{-100}
=-1+2/5
$